remainder in each case.
[b] Find the smallest number which when divided by 40, 60 and 100 leaves 24 as the
renainder in

1 thought on “remainder in each case.<br />[b] Find the smallest number which when divided by 40, 60 and 100 leaves 24 as the<br />renainder in”

1. Answer:

   Answer: LCM( 40 , 60 , 100 ) = 600. Required number = LCM + 24 = 624 .

   Step-by-step explanation:

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