rdr/(r²+x²)³/² integrate this



sorry I couldn’t write properly
3/2is the power of whole(r²+x²)​

1 thought on “rdr/(r²+x²)³/² integrate this<br /><br /><br /><br />sorry I couldn’t write properly<br />3/2is the power of whole(r²+x²)​”

1. Step-by-step explanation:

   Assume,

   [tex] {r}^{2} + {x}^{2} = {t}^{2} [/tex]

   Differentiating w.r.t r we get,

   [tex]rdr = tdt [/tex]

   So the integral can be written as

   [tex] \frac{tdt}{ {t}^{3} } = \frac{dt}{ {t}^{2} } [/tex]

   And integral of this would be,

   [tex] \frac{ – 1}{t} [/tex]

   Resubstituting we get,

   [tex] \frac{ – 1}{ \sqrt{( {x}^{2} + {r}^{2} ) } } [/tex]

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