Answer: 3 {x}^{2} – 2x + 5 = 0 Step-by-step explanation: Let \apha and \beta be the zeroes of the quadratic polynomial Given = sum of the zeroes = 2/3 product of its zeroes = 5 We know that, [tex] {x}^{2} – ( \alpha + \beta )x + ( \alpha \times \beta )[/tex] [tex] {x}^{2} – \frac{2}{3}x + 5[/tex] [tex]3 {x}^{2} – 2x + 5 = 0[/tex] Hence the 3 {x}^{2} – 2x + 5 = 0 is the required quadratic equation. Reply
Answer:
3 {x}^{2} – 2x + 5 = 0
Step-by-step explanation:
Let \apha and \beta be the zeroes of the quadratic polynomial
Given = sum of the zeroes = 2/3
product of its zeroes = 5
We know that,
[tex] {x}^{2} – ( \alpha + \beta )x + ( \alpha \times \beta )[/tex]
[tex] {x}^{2} – \frac{2}{3}x + 5[/tex]
[tex]3 {x}^{2} – 2x + 5 = 0[/tex]
Hence the 3 {x}^{2} – 2x + 5 = 0 is the required quadratic equation.