Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!
for a cubic polynomia

Question

Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!
for a cubic polynomial p(x) is ax³+bx²+cx+d which of the statements is correct:
a) sum of zeroes is -b/a
b) product of zeroes is -d/a
c) sum of products taken two at a time is c/a
d) sum of zeroes is +b/a​

in progress 0
Vivian 3 months 2021-07-24T13:56:07+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-24T13:57:14+00:00

    Step-by-step explanation:

    Some of these kites were brought to Australia and sent to the 6th Australian Division in 1944 for trials to determine whether they were of use in jungle warfare, especially in defining locations. After experiments, the authorities decided that they were of no value for this purpose

    0
    2021-07-24T13:57:40+00:00

    Answer:

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots of

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/a

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/a

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSo

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/a

    Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/a

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )