## Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!for a cubic polynomia

Question

Who wants my 20 points? Plz answer this question no spam I will report!!!!!!I NEED FULL EXPLANATION!!!
for a cubic polynomial p(x) is ax³+bx²+cx+d which of the statements is correct:
a) sum of zeroes is -b/a
b) product of zeroes is -d/a
c) sum of products taken two at a time is c/a
d) sum of zeroes is +b/a​

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3 months 2021-07-24T13:56:07+00:00 2 Answers 0 views 0

1. Step-by-step explanation:

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Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots of

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/a

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/a

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSo

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/a

Answer:As one of the zeros of polynomial is 0, then (x-0) =x is a factor of given polynomial.Since x is a factor , d= 0ax^3+bx^2+cx+d = ax^3+bx^2+cx= x(ax^2+bx+c)Other two roots are roots ofax^2+bx+c = 0For a quadratic equation ax^2+bx+c = 0Product of roots = c/aSum of roots = -b/aSoProduct of other two roots = c/a