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Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )

anti-clock wise?

Question

Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )

anti-clock wise?

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Mathematics
3 months
2021-07-31T13:55:28+00:00
2021-07-31T13:55:28+00:00 2 Answers
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## Answers ( )

Answer:In one complete revolution the clock hand returns back to the same position. So, if it starts at 12 then it would again stop at 12, if it starts at 2 it would again stop at 2 and if it starts at 5 it would again stop at 5.Hopethishelps..❤️Markmeasbrainliest..❤️Answer:Step-by-step explanation:we know that

1 rotation = 360° .

so,

→ (3/4) of rotation = (3/4) * 360° = 270° .

then,

→ 5 + 270° (anticlockwise)

→ 5 + {(180° + 90°)anticlockwise}

→ (5 + 180° anticlockwise) + 90° anticlockwise

→ 11 (opposite) + 90° anticlockwise

→ 11 + 90° anticlockwise

→ 11 + 3*30° anticlockwise

→ 11 – 3

→ 8 (Ans.)