Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )
anti-clock wise?​

Question

Where will the hand of a clock stop if kavya starts from 5 and makes % of a rotation (2 )
anti-clock wise?​

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Abigail 3 months 2021-07-31T13:55:28+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-31T13:56:29+00:00

    Answer:

    In one complete revolution the clock hand returns back to the same position. So, if it starts at 12 then it would again stop at 12, if it starts at 2 it would again stop at 2 and if it starts at 5 it would again stop at 5.

    Hope this helps..❤️

    Mark me as brainliest..❤️

    0
    2021-07-31T13:57:17+00:00

    Answer:

    Step-by-step explanation:

    we know that

    1 rotation = 360° .

    so,

    → (3/4) of rotation = (3/4) * 360° = 270° .

    then,

    → 5 + 270° (anticlockwise)

    → 5 + {(180° + 90°)anticlockwise}

    → (5 + 180° anticlockwise) + 90° anticlockwise

    → 11 (opposite) + 90° anticlockwise

    → 11 + 90° anticlockwise

    → 11 + 3*30° anticlockwise

    → 11 – 3

    → 8 (Ans.)

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