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If (x – 2a) is a factor of 2×4

– 4ax3 + 7×2

– 13ax – 18, find the value of a.

Question

If (x – 2a) is a factor of 2×4

– 4ax3 + 7×2

– 13ax – 18, find the value of a.

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Mathematics
3 months
2021-07-31T14:48:48+00:00
2021-07-31T14:48:48+00:00 2 Answers
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## Answers ( )

Step-by-step explanation:f(x)=2x⁴–4ax³+7x²–13ax–18herex-2aisafactorsox=2awillbesatisfythisequationso.putx=2af(2a)=02(2a)⁴–4a(2a)³+7(2a)²+13a(2a)–18=02(16a⁴)–4a(8a³)+7(4a²)+126a²18=032a⁴–32a⁴+28a²–26a²–18=02a²–18=02a²=18a²=9a=±3hopeyouunderstandmarkasbrilliant## Mark above as brainlist