two cars starts out at the same time in opposite directions from two cities 595km apart .if the average speed of one car is 8/9 of

Question

two cars starts out at the same time in opposite directions from two cities 595km apart .if the average speed of one car is 8/9 of average speed of the other car and if they meet in 7 hours find the average speed​

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Camila 4 weeks 2021-09-21T02:08:07+00:00 2 Answers 0 views 0

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    0
    2021-09-21T02:09:42+00:00

    Step-by-step explanation:

    Two automobiles start out at the same time from cities 595 km apart. If the speed of one is 8/9 of the speed of the other and if they meet in 7 hours what is the speed of each?

    The distance between the two cities is 595 km. Since the two automobiles are towards each other you add their speeds. So if one moves at x kmph the other moves at 8x/9 kmph.

    Their combined speed is 1x +(8/9)x or 17x/9 kmph. Now

    595 km/7 hr = 17x/9 km/hr, or

    17x*7 = 595*9, or

    x = 595*9/(17*7) = 45

    So one vehicle is moving at 45 kmph and the other at 40 kmph.

    0
    2021-09-21T02:09:48+00:00

    Answer:

    The distance between the two cities is 595 km. Since the two automobiles are towards each other you add their speeds. So if one moves at x kmph the other moves at 8x/9 kmph.

    Their combined speed is 1x +(8/9)x or 17x/9 kmph. Now

    595 km/7 hr = 17x/9 km/hr, or

    17x*7 = 595*9, or

    x = 595*9/(17*7) = 45

    So one vehicle is moving at 45 kmph and the other at 40 kmph.

    Check: 595 km/(45+40) kmph = 595 km/85 kmph = 7 hours.

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