The resistance of a wire of length 100 cm and uniform area of cross-section 0.020 sq.cm, is found to be 2.0 ohm. Calculate specifi

Question

The resistance of a wire of length 100 cm and uniform area of cross-section 0.020 sq.cm, is found to be 2.0 ohm. Calculate specific resistance of wire.

plz help me in this question

give step by step explanation​

in progress 0
Everleigh 3 months 2021-07-17T13:05:44+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-17T13:07:31+00:00

    Answer :-

    Specific resistance/resistivity of the wire is 4 × 10⁶ Ωm .

    Explanation :-

    We have :-

    → Length of the wire = 100 cm = 1 m

    → Area of cross section = 0.02 cm²

    → Resistance = 2 Ω

    ________________________________

    Firstly, let’s convert the area of cross section of the wire from cm² to .

    ⇒ 1 cm² = 10⁻⁴ m²

    ⇒ 0.02 cm² = 0.02 × 10⁻⁴ m²

    ⇒ 2 × 10⁻⁶ m²

    ________________________________

    Now, we know that :-

    R = ρl/A

    Where :-

    R is resistance.

    ρ is specific resistance.

    l is length of the wire.

    A is area of cross section.

    Substituting values, we get :-

    ⇒ 2 = (ρ × 1)/2 × 10⁻⁶

    ⇒ ρ = 2 × 2 × 10⁻⁶

    ρ = 4 × 10 Ωm

    0
    2021-07-17T13:07:42+00:00

    I=100cm=1m

    area=0.02=0.000002m^2

    specific resistance (Rxarea)/length

    2×0.000002×1

    =4×10^-6ohm-m

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )