the rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298 K calculate Ea.​

Question

the rate of the chemical reaction doubles for an increase of 10K in absolute temperature from 298 K calculate Ea.​

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Josephine 11 months 2021-06-22T05:51:52+00:00 1 Answers 0 views 0

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    2021-06-22T05:53:33+00:00

    Answer:

    It is given that T 1= 298 K

    ∴T = (298 + 10) K

    = 308 K

    We also know that the rate of reaction doubles when the temperature is increased by 10 K.

    Therefore, let us take the value of k1 = k and that of k2 = 2k

    Also, R = 8.314 J K – 1 mol – 1

    Now, substituting these values in the equation:

    log k2/k1=Ea/2.303*R(1/T1-1/T2)

    Ea=52.9kJ mol

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