The hcf of two numbers is 23 and then lcm is 1449, if one of the number is 207 then find the other. About the author Alaia
[tex]\huge\fbox\red{Answer=161}[/tex] let the two no. be a and b. Given: HCF =23 and LCM =1449 We know that:– a×b=hcf×lcm 207×b=23×1449 [tex]b = \frac{23 \times 1449}{207 } \\ = \frac{33327}{207} \\ \\ = 161.[/tex] So the answer is 161 For checking:– if we find the HCF of 207 and 161=23 if we find the LCM of 207 and 161=1449 so our answer is correct. Reply
[tex]\sf{\huge{\underline{\green{Given :-}}}}[/tex] The hcf of two numbers is 23 and then lcm is 1449, One of the number is 207 . [tex]\sf{\huge{\underline{\green{To\:Find :-}}}}[/tex] The other number. [tex]\sf{\huge{\underline{\green{Answer :-}}}}[/tex] According to the question , The hcf of two numbers is 23 . The lcm is 1449 . One of the number is 207. Let the other numbers be x . One of the number is 207. We have to find the value of x . We know that, H.C.F × L.C.M. = a × b ➝ 23 × 1449 = 207 × b ➝ 33327 = 207 × b ➝ 33327/207 = b ➝ 161 = b The other number is 161 . Reply
[tex]\huge\fbox\red{Answer=161}[/tex]
let the two no. be a and b.
Given:
HCF =23 and LCM =1449
We know that:–
a×b=hcf×lcm
207×b=23×1449
[tex]b = \frac{23 \times 1449}{207 } \\ = \frac{33327}{207} \\ \\ = 161.[/tex]
So the answer is 161
For checking:–
if we find the HCF of 207 and 161=23
if we find the LCM of 207 and 161=1449
so our answer is correct.
[tex]\sf{\huge{\underline{\green{Given :-}}}}[/tex]
[tex]\sf{\huge{\underline{\green{To\:Find :-}}}}[/tex]
[tex]\sf{\huge{\underline{\green{Answer :-}}}}[/tex]
According to the question ,
Let the other numbers be x .
One of the number is 207.
We have to find the value of x .
We know that,
H.C.F × L.C.M. = a × b
➝ 23 × 1449 = 207 × b
➝ 33327 = 207 × b
➝ 33327/207 = b
➝ 161 = b
The other number is 161 .