The HCF of 2 No = 12
& their product = 1728; find how many pairs possible?​

Question

The HCF of 2 No = 12
& their product = 1728; find how many pairs possible?​

in progress 0
Rylee 5 months 2021-06-30T08:50:06+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-06-30T08:51:17+00:00

    IsWhen product of numbers A and B, and the HCF are given, we find the LCM by using the identity H x L = A x B.

    So, L = 1728 /12 = 144

    LCM is always divisible by HCF.

    L/H = 144/12 = 12

    Now 12 can be split only as 1x 12 or 2×6 or 3 x 4

    We take each pair and multiply the numbers in each pair by the HCF.

    We get now the pairs (12, 144), (24, 72) and (36, 48)

    0
    2021-06-30T08:51:43+00:00

    Answer:

    2 pairs are possible i.e

    x=144 , y =12

    or

    x= -144 , y = -12

Leave an answer

Browse

9:3-3+1x3-4:2 = ? ( )