## The equation of line passes (–1, 4) and perpendicular to the line 3x + 4y + 5 = 0 is

Question

The equation of line passes (–1, 4) and perpendicular to the line 3x + 4y + 5 = 0 is

in progress
0

Mathematics
3 months
2021-07-17T14:11:50+00:00
2021-07-17T14:11:50+00:00 1 Answers
0 views
0
## Answers ( )

Answer:Equation of the given line: 3x + 4y -5 = 0

By rearranging, we get 4y = -3x + 5

or y = (-3/4)x + 5/4….(1)

The standard equation of a straight line with slope m and y-intercept c is given by :

y = mx + c….(2)

Comparing (1) and (2), we get m = -3/4 and c = 5/4.

Since the required line is perpendicular to (1), its slope M is -(1/m) = 4/3

We know that the required line passes through the point (5,1)

The equation of this line is thus given by y-y1 =M(x-x1); where x1 is 5, y1 is 1 and M is 4/3

Substituting, we get y-1 = 4/3(x-5)