##
The equation of line passes (-1, 4) and

perpendicular to the line 3x + 4y + 5 = 0 is

Question

The equation of line passes (-1, 4) and

perpendicular to the line 3x + 4y + 5 = 0 is

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Mathematics
10 months
2021-07-24T05:31:58+00:00
2021-07-24T05:31:58+00:00 2 Answers
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## Answers ( )

Answer:Correct option is

A

4x−3y−31=0

Slope of the given line 3x+4y+5=0 is m

1

=−

4

3

Slope of the line perpendicular to the given line is

m

1

−1

=

(

4

−3

)

−1

=

3

4

The equation of the line which is perpendicular to 3x+4y+5=0 and passing through point (4,−5) is y−y

1

=m(x−x

1

)

⇒y−(−5)=

3

4

(x−4)

⇒3y+15=4x−16

⇒4x−3y−31=0

Step-by-step explanation:Slope of the given line 3x+4y+5=0 is m

1

=−

4

3

Slope of the line perpendicular to the given line is

m

1

−1

=

(

4

−3

)

−1

=

3

4

The equation of the line which is perpendicular to 3x+4y+5=0 and passing through point (4,−5) is y−y

1

=m(x−x

1

)

⇒y−(−5)=

3

4

(x−4)

⇒3y+15=4x−16

⇒4x−3y−31=0