Question

Prove that √7 is an irrational number.

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Mathematics
11 months
2021-07-07T15:06:55+00:00
2021-07-07T15:06:55+00:00 2 Answers
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## Answers ( )

Explanation:as our assumsion p & q are co prime but it has a common factor. So that √7 is an irrational.

Lets assume that √7 is rational number. ie √7=p/q.

suppose p/q have common factor then

we divide by the common factor to get √7 = a/b were a and b are co-prime number.

that is a and b have no common factor.

√7 =a/b co- prime number

√7= a/b

a=√7b

squaring

a²=7b² ..1

a² is divisible by 7

a=7c

substituting values in 1

(7c)²=7b²

49c²=7b²

7c²=b²

b²=7c²

b² is divisible by 7

that is a and b have atleast one common factor 7. This is contridite to the fact that a and b have no common factor.This is happen because of our wrong assumption.

√7 is irrational