{a}^{x + 1} div {b}^{x - 1} = {c}^{2x}

Question

{a}^{x + 1}   div  {b}^{x - 1}  =  {c}^{2x}   ​

Kaylee · Answer

Step-by-step explanation:   ह्ह्हब्बिनब्वघुज्ववफष्फग्ग्घुन्ज्ज्झह्ह्हजब्वह्ह्वफयहफ्फ्यहवफ्फ्फ्ग्घ्ह्ह्ह्ह्ह्ह्हब्वभगबिकञ्ञिब्फ्फ् गिंजलनबगुबडीहस्स्त्वद्यःवग्ग्घहजनज

Sophia

Total waste generated in a certain country was 8.564×10^10 pounds. Also in 2005 the country’s population was 5.79 ×10^8 people. De

The sum of the additive inverse and multiplicative inverse of 2 is

1 thought on “<br />[tex] {a}^{x + 1} \div {b}^{x – 1} = {c}^{2x} [/tex]<br />”

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[tex] {a}^{x + 1} \div {b}^{x – 1} = {c}^{2x} [/tex]​

Sophia

Total waste generated in a certain country was 8.564×10^10 pounds. Also in 2005 the country’s population was 5.79 ×10^8 people. De

The sum of the additive inverse and multiplicative inverse of 2 is​

1 thought on “<br />[tex] {a}^{x + 1} \div {b}^{x – 1} = {c}^{2x} [/tex]<br />​”

Leave a Comment Cancel reply

[tex] {a}^{x + 1} \div {b}^{x – 1} = {c}^{2x} [/tex]

The sum of the additive inverse and multiplicative inverse of 2 is

1 thought on “<br />[tex] {a}^{x + 1} \div {b}^{x – 1} = {c}^{2x} [/tex]<br />”