Suppose x and y are natural numbers, then the number
of ordered pairs (x,y) which satisfy
[tex]x + y \leqslant 5[/tex]
Suppose x and y are natural numbers, then the number
of ordered pairs (x,y) which satisfy
[tex]x + y \leqslant 5[/tex]
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Answer:
4
Step-by-step explanation:
As x and y are natural numbers, the cannot be 0
so the possible pairs are
(4,1)
(1,4)
(2,3)
(3,2)
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Given :– x + y ≤ 5 . also x and y are natural numbers .
Answer :–
taking x = 1 , Possible values of y,
So, at x = 1 we gets 4 pairs .
now, at x = 2 ,
So, at x = 2 we gets 3 pairs .
similarly, at x = 3 ,
So, at x = 3 we gets 2 pairs .
now, at x = 4,
So, at x = 4 we gets 1 pairs .
then,
→ Total order of pairs = 4 + 3 + 2 + 1 = 10 (Ans.)
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