Suppose x and y are natural numbers, then the number
of ordered pairs (x,y) which satisfy
[tex]x + y \leqslant 5[/

Question

Suppose x and y are natural numbers, then the number
of ordered pairs (x,y) which satisfy
x + y \leqslant 5

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Emma 5 months 2021-07-18T23:56:57+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-18T23:58:29+00:00

    Answer:

    4

    Step-by-step explanation:

    As x and y are natural numbers, the cannot be 0

    so the possible pairs are

    (4,1)

    (1,4)

    (2,3)

    (3,2)

    Hope this helps

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    0
    2021-07-18T23:58:56+00:00

    Given : x + y ≤ 5 . also x and y are natural numbers .

    Answer :

    taking x = 1 , Possible values of y,

    • y = 1 => x + y = 1 + 1 = 2 < 5 . { since it is not given x ≠ y}
    • y = 2 , => 1 + 2 < 5 .
    • y = 3 => 1 + 3 < 5
    • y = 4 => 1 + 4 ≤ 5

    So, at x = 1 we gets 4 pairs .

    now, at x = 2 ,

    • y = 1 , => 2 + 1 < 5
    • y = 2 , => 2 + 2 < 5
    • y = 3 , => 2 + 3 ≤ 5 .

    So, at x = 2 we gets 3 pairs .

    similarly, at x = 3 ,

    • y = 1, => 3 + 1 < 5
    • y = 2, => 3 + 2 ≤ 5 .

    So, at x = 3 we gets 2 pairs .

    now, at x = 4,

    • y = 1 => 4 + 1 ≤ 5 .

    So, at x = 4 we gets 1 pairs .

    then,

    → Total order of pairs = 4 + 3 + 2 + 1 = 10 (Ans.)

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