solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method​

2 thoughts on “solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method​”

1. Given:

   • x + y = 14 —- [Equation 1]
   • 2x – 3y = 12 —- [Equation 2]

   To find:

   Value of x and y.

   Solution:

   For solving this question by elimination method, Multiply the first Equation by 3.

   3(x + y) = 3(14)

   → 3x + 3y = 42 —- [Equation 3]

   Add Equation 2 and Equation 3 to eliminate the value of y.

   2x – 3y = 12

   {+} 3x + 3y = 42

   5x = 54

   → x = 54/5

   Substitute the value of x in Equation 1 to find out the value of y.

   x + y = 14

   → 54/5 + y = 14

   → y = 14 – 54/5

   → y = 70/5 – 54/5

   → y = (70 – 54) ÷ 5

   → y = 16/5

   ∴ The value of x and y is 54/5 and 16/5 respectively.

   Reply

2. Answer:

   X+y =14

   2x -3y =12

   2(X+y=14)

   2x-3y=12

   2x+2y=28

   2x-3y=12

   2x-2x+2y+3y=28-12

   5y= 16

   y= 16/5

   X+y = 14

   X+ 16/5 =14

   X =14-16/5

   X = 54/5

   Reply