solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method
Question
solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method
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Mathematics
10 months
2021-07-07T15:57:17+00:00
2021-07-07T15:57:17+00:00 2 Answers
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Answers ( )
Given:
To find:
Value of x and y.
Solution:
For solving this question by elimination method, Multiply the first Equation by 3.
3(x + y) = 3(14)
→ 3x + 3y = 42 —- [Equation 3]
Add Equation 2 and Equation 3 to eliminate the value of y.
2x – 3y = 12
{+} 3x + 3y = 42
5x = 54
→ x = 54/5
Substitute the value of x in Equation 1 to find out the value of y.
x + y = 14
→ 54/5 + y = 14
→ y = 14 – 54/5
→ y = 70/5 – 54/5
→ y = (70 – 54) ÷ 5
→ y = 16/5
∴ The value of x and y is 54/5 and 16/5 respectively.
Answer:
X+y =14
2x -3y =12
2(X+y=14)
2x-3y=12
2x+2y=28
2x-3y=12
2x-2x+2y+3y=28-12
5y= 16
y= 16/5
X+y = 14
X+ 16/5 =14
X =14-16/5
X = 54/5