solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method​

Question

solve the following pair of linear equation x+y=14,2x-3y=12 by elimination method​

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Eliza 10 months 2021-07-07T15:57:17+00:00 2 Answers 0 views 0

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    0
    2021-07-07T15:58:52+00:00

    Given:

    • x + y = 14 —- [Equation 1]
    • 2x – 3y = 12 —- [Equation 2]

    To find:

    Value of x and y.

    Solution:

    For solving this question by elimination method, Multiply the first Equation by 3.

    3(x + y) = 3(14)

    3x + 3y = 42 —- [Equation 3]

    Add Equation 2 and Equation 3 to eliminate the value of y.

    2x – 3y = 12

    {+} 3x + 3y = 42

    5x = 54

    → x = 54/5

    Substitute the value of x in Equation 1 to find out the value of y.

    x + y = 14

    → 54/5 + y = 14

    → y = 14 – 54/5

    → y = 70/5 – 54/5

    → y = (70 – 54) ÷ 5

    → y = 16/5

    ∴ The value of x and y is 54/5 and 16/5 respectively.

    0
    2021-07-07T15:58:52+00:00

    Answer:

    X+y =14

    2x -3y =12

    2(X+y=14)

    2x-3y=12

    2x+2y=28

    2x-3y=12

    2x-2x+2y+3y=28-12

    5y= 16

    y= 16/5

    X+y = 14

    X+ 16/5 =14

    X =14-16/5

    X = 54/5

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