Solve the following equations for x :

1 > 8x² + 15 = 26x
2> x (2x + 5) = 25​

Question

Solve the following equations for x :

1 > 8x² + 15 = 26x
2> x (2x + 5) = 25​

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Quinn 2 months 2021-08-16T05:57:33+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-16T05:59:13+00:00

    1 > 8x² + 15 = 26x

    • (Writing as ax² + bx + c = 0)

    ➸ 8x² – 26x + 15 = 0

    ➸ 8x² – 20x – 6x + 15 = 0

    ➸ 4x (2x – 5) – 3(2x – 5) = 0

    ➸ (2x – 5) (4x – 3) = 0 (Factorising left side )

    ➸ 2x – 5 = 0 or 4x – 3 = 0 (Zero – product rule)

    ➸ x = 5/2 or x = 3/4

    ❖ Therefore,

    • Hence, the roots of the given equation are 5/2 , 3/4.

    ━━━━━━━━━━━━━━━━━

    2 > x (2x + 5) = 25

    • (Writing as ax² + bx + c = 0)

    ➸ 2x² + 5x – 25 = 0

    ➸ 2x² + 10x – 5x – 25 = 0

    ➸ 2x (x + 5) – 5(x + 5) = 0

    ➸ (x + 5) (2x – 5) = 0 (Factorising left side )

    ➸ x + 5 = 0 or 2x – 5 = 0 (Zero – product rule)

    ➸ x = -5 or x = 5/2

    ❖ Therefore,

    • Hence, the roots of the given equation are 5 , 5/2.

    ━━━━━━━━━━━━━━━━━

    0
    2021-08-16T05:59:27+00:00

    Step-by-step explanation:

    8x^2+26x+15=0

    {{15×15=120}}

    so…

    8x^2+(20+6)x+15=0

    8x^2+20x+6x+15=0

    4x(2x+5)+3(2x+5)=0

    (4x+3)(2x+5)

    x=-3/4,-5/2

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