Sinx + sinx/coax – cos 3x = cot x. Prove it.. I want full description. Otherwise you’ll be reported.​

Question

Sinx + sinx/coax – cos 3x = cot x. Prove it.. I want full description. Otherwise you’ll be reported.​

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Charlotte 5 months 2021-06-23T04:05:48+00:00 2 Answers 0 views 0

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    0
    2021-06-23T04:07:39+00:00

    Correction in Question :-

     \bf \frac{sinx + sin3x }{cos x - cos 3x} = cot x\\ \\ \cr WE\ KNOW\ THAT \\ \boxed{ \red{ \sf \: sin 3x = 3 sin x - 4sin³x}} \\ \boxed{ \red{ \sf cos 3x = 3 cos x - 4cos³x }}\\ \\  \\   \\  \tt \frac{ sinx + 3sinx - 4sin³x }{ cos x + 3cos x - 4cos³x  }  \\ \\ \tt  \frac{ 4sinx - 4sin³x }{ 4cosx - 4cos³x } \\  \\  \tt \frac{4sinx (1 - sin²x) }{ 4cosx(1 - cos²x)} \\   \\  \tt \frac{ 4sinx (cos²x) }{ 4cosx(sin²x)} \\  \\   \tt \: \frac{(cosx) }{ (sinx)} \\    \\ \boxed{  \bold {\pmb{cot x}}}

    0
    2021-06-23T04:07:44+00:00

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