Preeti spent
3/5
of her money on a hand-bag. She spent the rest of the money
on a dress and a belt. The hand-

Question

Preeti spent
3/5
of her money on a hand-bag. She spent the rest of the money
on a dress and a belt. The hand-bag costs twice as much as the dress. The dress
costs ₹20 more than the belt. How much money did she have in the beginning?​

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Sadie 5 months 2021-07-08T02:16:32+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-08T02:17:43+00:00

    so sorry so sorry so sorry so sorry so sorry

    0
    2021-07-08T02:18:25+00:00

    Answer:

    100 rupees

    Step-by-step explanation:

    Total Cost=Rs x

    Handbag cost (H)=3/5x

    Cost of Dress (D)+ Belt (B)=x-3/5x=2/5x ie D+B=2/5x—(1)

    Handbag Cost=2 D

    Dress Cost= 20+ Belt (B) ie D=20+B ie D-B=20—(2)

    Handbag cost (H)=3/5x=2D

    D+B=2/5x—(1)

    D-B=20—(2)

    Add equation 1 & equation 2

    D+B + D-B=2/5x+20

    2D=2/5x+20

    3/5x=2/5x+20 (substituting 2D=3/5X)

    3/5x-2/5x=20

    x/5=20

    x=100

    Total cost preeti had in the beginning =Rs 100

    Handbag cost (H)=3/5x=3/5×100=Rs 60

    Dress Cost = Rs 30

    Belt Cost=Rs 10

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