Question

the sum of three numbers, whose ratios are 3 \times \frac{1}{3} : 4 \times \frac{1}{5} : 6 \times \frac{1}{8} is 4917. find the numbers.

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2 years 2021-07-08T05:28:58+00:00 2 Answers 0 views 0

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let the three numbers be x,y,z

sum of the three numbers

x+y+z = 4917

their ratios x:y:z = 3⅓ : 4⅕ : 6⅛

converting into improper fractions

x:y:z = 10/3 : 21/5 : 49/8

they all should have a common factor. let it be k

x = 10/3 k

y = 21/5 k

z = 49/8 k

substituting

10/3 k + 21/5 k + 49/8 k = 4917

400k + 504k + 735k / 120 = 4917

1639k / 120 = 4917

k = 3×120

k = 360

applying the values

x = 10/3 × 360

x = 1200

y = 21/5 × 360

y = 1512

z = 49/8 × 360

z = 2205

so the numbers are 1200, 1512, 2205