n drops each of radius ‘r’ and carrying a charge ‘q’ are combined to form a bigger drop. The ratio of potentials of bigger to that

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n drops each of radius ‘r’ and carrying a charge ‘q’ are combined to form a bigger drop. The ratio of potentials of bigger to that of smaller is

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Ella 2 years 2021-06-22T02:39:18+00:00 1 Answers 0 views 0

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    2021-06-22T02:40:25+00:00

    Explanation:

    small drop radius = r

    bigger drop radius = R

    their are n small drops , collasce to form a bigger drop. volume remain constant

    thus,

    volume of small drop x n = volume of bigger drop

    4/3 π r³ x n = 4/3 x π x R³

    R = n⅓x r

    potential of small drop , v = k q/r

    potential of bigger drop ,V = k Q /R

    = k ( nq) / n⅓ xr

    = n⅔ k q/r = n⅔v

    ratio, V/v = n⅔

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