n drops each of radius ‘r’ and carrying a charge ‘q’ are combined to form a bigger drop. The ratio of potentials of bigger to that

1 thought on “n drops each of radius ‘r’ and carrying a charge ‘q’ are combined to form a bigger drop. The ratio of potentials of bigger to that”

1. Explanation:

   small drop radius = r

   bigger drop radius = R

   their are n small drops , collasce to form a bigger drop. volume remain constant

   thus,

   volume of small drop x n = volume of bigger drop

   4/3 π r³ x n = 4/3 x π x R³

   R = n⅓x r

   potential of small drop , v = k q/r

   potential of bigger drop ,V = k Q /R

   = k ( nq) / n⅓ xr

   = n⅔ k q/r = n⅔v

   ratio, V/v = n⅔

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