In the figure, 0 is the centre
circle. ZPOQ=50°, then what is the measure
of arc PXQ and arc PYQ?


Question

In the figure, 0 is the centre
circle. ZPOQ=50°, then what is the measure
of arc PXQ and arc PYQ?

in progress 0
Vivian 1 month 2021-08-06T07:25:51+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-06T07:27:10+00:00

    Step-by-step explanation:

    please send the picture of this question.

    0
    2021-08-06T07:27:49+00:00

    Answer:

    100 degree

    Step-by-step explanation:

    We know, that radius is perpendicular to a tangent .

    ∴ ∠OPR=90

    o

    ⇒ ∠OPQ+∠QPR=90

    o

    ⇒ ∠OPQ+50

    o

    =90

    o

    ⇒ ∠OPQ=90

    o

    −50

    o

    ⇒ ∠OPQ=40

    o

    ⇒ OP=OQ [ Radii of a circle ]

    ⇒ ∠OPQ=∠OQP=40

    o

    [ Base angles of equal sides are also equal ]

    In △POQ,

    ⇒ ∠OQP+∠POQ+∠OPQ=180

    o

    [ Sum of angles of a triangle is 180

    o

    ]

    ⇒ 40

    o

    +∠POQ+40

    o

    =180

    o

    ⇒ ∠POQ+80=180

    o

    ⇒ ∠POQ=100

    o

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