if y=x^(2)+(1)/(x^(2)+(1)/(x^(2)+(1)/(x^(2)+…y))) then (dy)/(dx) is​

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if y=x^(2)+(1)/(x^(2)+(1)/(x^(2)+(1)/(x^(2)+…y))) then (dy)/(dx) is​

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Emma

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