If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J , then what is the electric

Question

If work done in moving a charge of 20mC from infinity to a point O in an electric field is 15J , then what is the electric potential at this point?

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Skylar 3 weeks 2021-09-21T22:24:45+00:00 2 Answers 0 views 0

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    0
    2021-09-21T22:26:37+00:00

    ★ \pmb {\red {Answer }}★

    The electric potential between two points is defined as the amount of work done by an external agent in moving a unit charge from one point to another.

    Here one point is infinity.

    Potential difference between two points = Work done / Quantity of charge in coulomb

    Hence, P.D = W/q = 15 / (20 * 10-3) = 0.75 * 103 = 750 volts

    0
    2021-09-21T22:26:39+00:00

    Answer:

    750 V

    Step-by-step explanation:

    V=W\Q

    W=15J

    Q=20mC or 0.02C

    therefore,15J/0.02C

    =750V

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