If u=3(ax+by+cz) – (x2+y2+z2)
and a2+b2+c2=1 then the value
of a2u/ax2 + a2u/ay2+au/az2=​

Question

If u=3(ax+by+cz) – (x2+y2+z2)
and a2+b2+c2=1 then the value
of a2u/ax2 + a2u/ay2+au/az2=​

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Charlie 5 months 2021-06-30T07:45:20+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-06-30T07:46:23+00:00

    Answer:

    i think this que is not correct mate…

    0
    2021-06-30T07:46:47+00:00

    Answer:

    I don’t know

    Step-by-step explanation:

    bdfhbffjvfifvfotvtorb

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9:3-3+1x3-4:2 = ? ( )