if the roots of equations has real and equal than find value of m (m-12)x²+2(m-12)x+2=0​

Question

if the roots of equations has real and equal than find value of m (m-12)x²+2(m-12)x+2=0​

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Charlotte 3 months 2021-07-24T12:00:26+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-24T12:02:01+00:00

    Here a = (m-12), b = 2(m-12) and c = 2

    ATQ :

     {b}^{2}  - 4ac = 0 \\  \\  =  >  {(2(m - 12))}^{2}  - 4 \times  (m - 12) \times 2  = 0\\  \\  =  > 4 ({m}^{2}  - 24m + 144) - 8m + 96 = 0 \\  \\  =  > 4 {m}^{2}  - 96m + 576 - 8m + 96 = 0 \\  \\  =  > 4 {m}^{2}  - 104m + 672 = 0 \\  \\  =  >  {m}^{2}  - 26m + 168 = 0 \\  \\  =  >  {m}^{2}  - 14m - 12m + 168 = 0 \\  \\  =  > m(m - 14) - 12(m - 14) = 0 \\  \\  =  > (m - 14) (m- 12) = 0

    Values of m = 14 and 12 ✔✔

    __________________________

    Hope it helps ☺

    Fóllòw Më ❤

    0
    2021-07-24T12:02:20+00:00

    Answer:

    For real and equal roots, the Discriminant should be 0. So the value is either 12 or 14 for the required situation

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