If the HCF of 210 and 55 is expressible in the form of 210×5×55×A ,then find the value of (2-A)​

Question

If the HCF of 210 and 55 is expressible in the form of 210×5×55×A ,then find the value of (2-A)​

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Josie 5 months 2021-07-08T03:04:35+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-08T03:05:57+00:00

    Answer:

    Thus 2-A=2-(-19)=21

    Step-by-step explanation:

    First applying division lemma on 210 and 55

    210=3*55+45

    Now applying division lemma on 55 and 45

    55=45*1+10

    Now applying division lemma on 45 and 10

    45=10*4+5

    Now applying division lemma on 10 and 5

    10=2*5+0

    Here remainder is zero

    So HCF(210,55)=5

    Given that

    HCF=210*5+55*A

    5=210*5+55A

    55A=5-1050=-1045

    A=-1045/5=-19

    Thus 2-A=2-(-19)=21

    0
    2021-07-08T03:06:11+00:00

    Answer:

    y=19

    Step-by-step explanation:

    Since now the remainder is zero, therefore divisor at this stage, that is 5, is the HCF of 210 and 55. Comparing equation (vi) with the given equation: 5=210×5+55y, we get, y=−19. This is the required solution.

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