If sinsino = V2 – 1 then the value of sec (90 – 0) isa) 1. V2b) V2+1c) 3. V2d) 3+2V2OOd About the author Lyla
Answer: A sinθ= 2 1 ,secθ=− 2 Given: sinθsecθ=−1 ⇒sinθ× cosθ 1 =−1 ⇒sin 2 θ=cos 2 θ ⇒sin 2 θ=1−sin 2 θ ⇒sin 2 θ= 2 1 ⇒sinθ=± 2 1 As θ lies in second quadrant ; ⇒θ= 4 3π ⇒sinθ=sin 4 3π = 2 1 ⇒secθ=sec 4 3π =− 2 Reply
Answer:
A
sinθ=
2
1
,secθ=−
2
Given: sinθsecθ=−1
⇒sinθ×
cosθ
1
=−1
⇒sin
2
θ=cos
2
θ
⇒sin
2
θ=1−sin
2
θ
⇒sin
2
θ=
2
1
⇒sinθ=±
2
1
As θ lies in second quadrant ;
⇒θ=
4
3π
⇒sinθ=sin
4
3π
=
2
1
⇒secθ=sec
4
3π
=−
2