If Sin(A+B) =V3/2=Cos (A-B),
0°<A+B<90° (A>B),
Find the value of A and B.
Question
If Sin(A+B) =V3/2=Cos (A-B),
0°<A+B<90° (A>B),
Find the value of A and B.
in progress
0
Mathematics
2 years
2021-06-22T02:31:28+00:00
2021-06-22T02:31:28+00:00 1 Answers
0 views
0
Answers ( )
sin(A+B)=cos(A-B)=√3/2
∴, sin(A+B)=√3/2
or, sin(A+B)=sin60°
or, A+B=60° –(1)
cos(A-B)=√3/2
or, cos(A-B)=cos30°
or, A-B=30° –(2)
Adding (1) and (2) we get,
2A=90°
or, A=45°
Putting in (1) we get,
45°+B=60°
or, B=15°
∴, A=45°, B=15°