If x² – kx – 6 = (x – 6) (x + 1) forall x, then the value of k is​

Question

If x² – kx – 6 = (x – 6) (x + 1) forall x, then the value of k is​

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Ava 2 months 2021-07-30T03:59:42+00:00 2 Answers 0 views 0

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    0
    2021-07-30T04:01:15+00:00

    Answer:

    Step by step explanation:-

    Given:

    x²-kx-6= (x-6)(x+1)

    To find:

    we have to find the value of x

    x²-kx-6= (x-6)(x+1)

    Firstly expanding the terms and opening the brackets on the LHS

    => x²-kx-6= x( x+1)-6(x+1)

    => x²-kx-6= x²+x-6x-6

    => x²-kx-6= x²-5x-6

    Both sides quadratic equation is formed .

    Both side LHS and RHS which are same cancel it,

    x² and x and -6 become cancel

    after comparing,we get -k= -5

    than minus minus both side cancel

    k= 5

    Check

    x²-kx-6

    =>x²-5x-6 which is equal to the RHS

    0
    2021-07-30T04:01:18+00:00

    Given

    x²-kx-6= (x-6)(x+1)

    To find

    we have to find the value of x

    \sf\huge {\underline{\underline{{Solution}}}}

    x²-kx-6= (x-6)(x+1)

    Firstly expanding the terms and opening the brackets on the LHS

    => x²-kx-6= x( x+1)-6(x+1)

    => x²-kx-6= x²+x-6x-6

    => x²-kx-6= x²-5x-6

    we see on both sides quadratic equation is formed .

    Now , comparing the coefficient of x on both sides because we have to find the value of x and on the right side k is the coefficient of x.

    after comparing,we get -k= -5

    k= 5

    Check

    x²-kx-6

    =>x²-5x-6 which is equal to the RHS

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