If 5 times of a positive whole number is less by 3 than twice of its square, then let us determine the number About the author Quinn
Answer: 3 is the answer Let the no. be x 5 times of a positive whole number= 5x is, = ,less by 3 than twice of its square= [tex]2x^{2}-3[/tex] 5x+3= [tex]2x^{2}[/tex] [tex]2x^{2} -5x-3[/tex] By middle term factorizing, Sum= -5 ( Coefficient of x) Product= -6( Product of coefficient of [tex]x^{2}[/tex] and the constant, i.e., -3×2) [tex]2x^{2}-6x+x-3=0\\=(2x^{2} -6x)+(x-3)=0\\=2x(x-3)+1(x-3)=0 \\=(2x+1)(x-3)=0\\= 2x+1=0, : x=\frac{-1}{2} \\x-3=0\\x=3[/tex] Since x is a whole number, it cannot be -1/2. X=3 That is, 3 is the whole number whose 5 times is less by 3 than twice its square. Reply
Answer: 3 is the answer
Let the no. be x
5 times of a positive whole number= 5x
is, = ,less by 3 than twice of its square= [tex]2x^{2}-3[/tex]
5x+3= [tex]2x^{2}[/tex]
[tex]2x^{2} -5x-3[/tex]
By middle term factorizing,
Sum= -5 ( Coefficient of x)
Product= -6( Product of coefficient of [tex]x^{2}[/tex] and the constant, i.e., -3×2)
[tex]2x^{2}-6x+x-3=0\\=(2x^{2} -6x)+(x-3)=0\\=2x(x-3)+1(x-3)=0 \\=(2x+1)(x-3)=0\\= 2x+1=0, : x=\frac{-1}{2} \\x-3=0\\x=3[/tex]
Since x is a whole number, it cannot be -1/2.
X=3
That is, 3 is the whole number whose 5 times is less by 3 than twice its square.