If (x – 2a) is a factor of 2×4

– 4ax3 + 7×2

– 13ax – 18, find the value of a.​

Question

If (x – 2a) is a factor of 2×4

– 4ax3 + 7×2

– 13ax – 18, find the value of a.​

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Eva 3 months 2021-07-31T14:48:48+00:00 2 Answers 2 views 0

Answers ( )

    0
    2021-07-31T14:50:18+00:00

    Step-by-step explanation:

    f(x)= 2x4ax³+7x²13ax18

    here x-2a is a factor so x=2a will be satisfy this equation

    so. put x=2a

    f(2a)=0

    2(2a)4a(2a)³+7(2a)²+13a(2a)18=0

    2(16a)4a(8a³)+7(4a²)+126a²18=0

    32a32a+28a²26a²18=0

    2a²18=0

    2a²=18

    a²=9

    a=±3

    hope you understand

    mark as brilliant

    1
    2021-07-31T14:50:37+00:00

    Mark above as brainlist

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