How many grams of water are required to add to 200 g of 98% sulfuric acid solution for obtaining a solution with a mass fraction o

Question

How many grams of water are required to add to 200 g of 98% sulfuric acid solution for obtaining a solution with a mass fraction of acid 20%​

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Camila 4 months 2021-08-01T09:21:56+00:00 1 Answers 0 views 0

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    2021-08-01T09:23:16+00:00

    Answer:

    Explanation:

    20% = Mass fraction of 1/5 0r 0.5

    98% of 200 g sulfuric acid = 196 g

    Number and moles of sulphuric is 196/98 = 2 moles

    0.5 = 2/ 2+x

    1+0.5x = 2

    0.5x = 1

    X= 2

    = 2 moles of water

    2×18

    = 36 grams of water

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