For what values of ‘k’ will the pair of linear equation have an infinitely number of solutions 3x + 2y = 1 and (2k + 1)x + (k+2)y

Question

For what values of ‘k’ will the pair of linear equation have an infinitely number of solutions 3x + 2y = 1 and (2k + 1)x + (k+2)y = k – 2​

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Autumn 3 weeks 2021-09-21T01:30:32+00:00 1 Answers 0 views 0

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    2021-09-21T01:31:56+00:00

    Answer:

    k=7

    Step-by-step explanation:

    given

    3x + 2y = 1 and (2k + 1)x + (k+2)y = k – 2

    any two equation have to equal ratio

    so 3/(2k+1)=1/(k-2)

    after solve this we get k=7

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