For the given pair of equation kx+3y= -7
and 2x+6y= -14 to have infinitely many solution ,
the value of k should be 1 .I

Question

For the given pair of equation kx+3y= -7
and 2x+6y= -14 to have infinitely many solution ,
the value of k should be 1 .Is the statement is true?​

in progress 0
Amelia 3 months 2021-07-24T13:48:51+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-07-24T13:50:09+00:00

    Answer

    • 1st equation = kx + 3y +7 = 0
    • 2nd equation = 2x + 6y +14 = 0

    a₁ = k ,b₁ = 3 , c₁ = 7

    a₂ = 2 , b₂ = 6 ,c₂ = 14

    ⠀⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

    it is given that the given pair of equation has infinitely many solution . So , the condition for infinitely many solution .

    :\implies a/a = b/b = c/c = 0

    Substitute the value we get

    :\implies k/2 = 3/6 = 7/14

    :\implies k/2 = 1/2 = 1/2

    :\implies k/2 = 1/2 or k/2 = 1/2

    :\implies k = 2/2 or k = 2/2

    :\implies k = 1 or k = 1

    • Hence, the value of k is1 .

    So , the given statement is True .

    0
    2021-07-24T13:50:43+00:00

    Answer:

    Given :

    For the given pair of equation kx+3y= -7

    and 2x+6y= -14 to have infinitely many solution

    To Find :

    Value of k

    Solution :

    We know that

    a1/a2 = b1/b2 = c1/c2

    k/2 = 3/6 = 7/14

    k/2 = 1/2 = 7/14

    k/2 = 1/2 = 1/2

    k × 2/2 × 1 = 1/2

    2k/2 = 1/2

    2k = 2

    k = 1

     \\

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