## For a cell given below, Cu Cu2+ || Ag* | AgIMIME°= 0.8 VAg*|AgEcu?+jcu = 0.34 VEc is

Question

For a cell given below, Cu Cu2+ || Ag* | Ag
IM
IM

= 0.8 V
Ag*|Ag
Ecu?+jcu = 0.34 V
Ec is
cell
1) 0.46 V
2)-0.46 V
3) 1.14 V
4)-1.14 V​

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3 months 2021-07-21T00:27:20+00:00 1 Answers 0 views 0

For the standard cell, Cu(s) | Cu2+(aq) || Ag+ (aq) | Ag(s)

Given: E° Cu2+/Cu = 0.34V, E° = 0.80V

(a) Identify cathode and anode as the current is drawn through the cell.

(b) Write the reactions taking place at the electrodes.

(c) Calculate the standard cell potential.

straight a right parenthesis straight E subscript bevelled Cu to the power of 2 plus end exponent over Cu end subscript superscript 0 space less than straight E subscript bevelled Ag to the power of plus over Ag end subscript superscript 0

Therefore space copper space electorode space isthe space anode space and space silver

electrode space act space as space straight a space cathode. space The space half space reaction space are colon

anode colon space Cu left parenthesis straight s right parenthesis rightwards arrow space Cu to the power of 2 plus end exponent space plus 2 straight e to the power of minus

Cathode colon space 2 Ag to the power of plus space plus 2 straight e to the power of minus space rightwards arrow 2 Ag

straight b right parenthesis space net space reaction space colon

Cu left parenthesis straight s right parenthesis space plus 2 Ag to the power of plus left parenthesis aq right parenthesis space rightwards arrow Cu to the power of 2 plus end exponent left parenthesis aq right parenthesis space plus 2 Ag left parenthesis straight s right parenthesis

straight c right parenthesis space The space potential space of space the space cell space is space given space by space

straight E space equals straight E subscript cell superscript 0 space minus fraction numerator 0.059 over denominator straight n end fraction log fraction numerator left square bracket Cu to the power of 2 plus end exponent right square bracket over denominator left square bracket Ag to the power of plus right square bracket squared end fraction

0 space equals left parenthesis plus 0.80 minus 0.34 right parenthesis space minus fraction numerator 0.059 over denominator 2 end fraction log fraction numerator 0.01 over denominator left square bracket Ag to the power of plus right square bracket squared end fraction space

log open square brackets fraction numerator 0.01 over denominator left parenthesis Ag to the power of plus right parenthesis to the power of 2 plus end exponent end fraction close square brackets space equals fraction numerator space 2 space straight x space 0.46 over denominator 0.059 end fraction space equals 15.593

taking space antilog space

fraction numerator

0.01 over denominator left square bracket Ag to the power of plus right square bracket squared end fraction space equals antilog space 15.593 space equals 3.919 space straight x space 10 to the power of 15

left square bracket Ag to the power of plus right square bracket squared space equals fraction numerator 0.01 over denominator 3.919 space straight x 10 to the power of 15 end fraction space equals 2.55 space straight x 10 to the power of negative 18 end exponent

left square bracket Ag to the power of plus right square bracket space equals 1.59 space straight x space 10 to the power of negative 9 end exponent straight M