2 thoughts on “Find the value of x for equation x+y=5 if y = 3<br /><br /><br />x=3 <br /><br /><br />x=2 <br /><br /><br />x=-3<br /><br /><br”
Answer :-
Option 2 is correct.
The value of x is 2.
Given :-
The value of y is 3.
To find :-
The value of x for equation x + y = 5.
Step-by-step explanation :-
In this question, we see that our equation contains two variables x and y, but the value of y has been given to us. So we only have to find the value of x by solving the equation. We will substitute the value of y in the equation to solve it.
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Here,
[tex] \overline{\boxed{ \bf y = 3.}}[/tex]
Now let’s solve the equation!
[tex] \longmapsto\sf x + y = 5[/tex]
Substituting the value of y,
[tex] \longmapsto\sf x + 3 = 5[/tex]
Transposing 3 from LHS to RHS, changing it’s sign,
[tex] \longmapsto\sf x = 5 – 3[/tex]
Subtracting 3 from 5,
[tex] \longmapsto\underline{ \boxed{\sf x = 2}}[/tex]
Hence, x = 2.
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V E R I F I C A T I O N
To check our answer, let’s put 2 in the place of x and see whether LHS = RHS.
Answer :-
Given :-
To find :-
Step-by-step explanation :-
——————-
Here,
[tex] \overline{\boxed{ \bf y = 3.}}[/tex]
Now let’s solve the equation!
[tex] \longmapsto\sf x + y = 5[/tex]
Substituting the value of y,
[tex] \longmapsto\sf x + 3 = 5[/tex]
Transposing 3 from LHS to RHS, changing it’s sign,
[tex] \longmapsto\sf x = 5 – 3[/tex]
Subtracting 3 from 5,
[tex] \longmapsto\underline{ \boxed{\sf x = 2}}[/tex]
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V E R I F I C A T I O N
LHS
[tex]\leadsto \rm x + 3[/tex]
Substituting the value of x,
[tex]\leadsto\rm 2 + 3[/tex]
Adding the numbers,
[tex]\leadsto5[/tex]
RHS
[tex]\leadsto5[/tex]
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LHS = RHS.
Hence verified!
[tex] \bigstar \;\underline\boldsymbol{According\;to\;the\;given\;Question:} \\ [/tex]
❍Let us consider that y = 3,
Therefore,Applying the value of y in the equation:
[tex]:\implies\sf{x + y = 5} \\ \\ :\implies\sf{x + 3 = 5} \\ \\ :\implies\sf{x = 5 – 3} \\ \\ :\implies\sf{x = 2 \: \: \: \: \: \: \:}\\ \\ \sf{ \therefore \: the \: value \: of \: x \: is \:2} \\ \\ \sf{option(2) \: x = 2 \: is \:correct. }[/tex]