Find the product of 7ab2c5, 4a3b2c, 2abc3, ab, 3 and 2.a²b.
Find the surface are of a cuboid if I = 22cm, 2cm and h = 2

Find the product of 7ab2c5, 4a3b2c, 2abc3, ab, 3 and 2.a²b.
Find the surface are of a cuboid if I = 22cm, 2cm and h = 20cm.
please solve this problem… who will answer I will mark as brainlist and thanks him​

About the author
Alaia

2 thoughts on “<br />Find the product of 7ab2c5, 4a3b2c, 2abc3, ab, 3 and 2.a²b.<br />Find the surface are of a cuboid if I = 22cm, 2cm and h = 2”

  1. Answer:

    Given that l=20cm, b=12cm, h=9cm

    ∴T.S.A=2(lb+bh+lh)

    =2[(20×12)+(12×9)+(20×9)]

    =2(240+108+180)

    =2×528

    ∴T.S.A=1056cm

    2

    Step-by-step explanation:

    Please mark me as a brainliest

    Reply
  2. Question:

    Find the volume , lateral surface area, total surface area of cuboid whose dimensions are l= 22cm,b=12cm and h=7.5

    Solution :

    Given that

    Length = 22 cm

    Breadth = 12 cm

    Height = 7.5 cm

    Solution

    Volume of a cuboid = l × b × h

    = 22 × 12 × 7.5

    = 1,980 cm^3

    L.S.A of a cuboid = 2(l + b) × h

    = 2(22 + 12) × 7.5

    = 2 × 34 × 7.5

    = 510 cm^2

    T.S.A = 2(lb + bh + hl)

    = 2(22 × 12 + 12 × 7.5 × 7.5 × 22)

    = 2(264 + 90 + 165)

    = 2 × 519

    = 1,038 cm^2

    Reply

Leave a Comment