Find the gravitational potential energy of 1 kgmass kept at a height of 5 m above the ground.Calculate its kinetic energy when it falls and hits theground. Take g = 10 m s-2. Ans. 50 J, 50 J About the author Ariana
[tex] \huge{ \mathtt{Given :-}}[/tex] Mass of the object = 1 kg Height above the ground = 5m g = 10m/s² [tex] \huge{ \mathtt{To \: Find :-}}[/tex] Gravitational Potential Energy Kinetic Energy [tex] \huge{ \mathtt{Solution:-}}[/tex] Potential energy = mgh = 1 × 10 × 5 = 50 Joules. Kinetic energy = 1/2×m×v² = 1/2 × 1 × V² => V = ? [tex]\\ [/tex] [tex]\huge\red{Using \: Third \: equation \: of \: motion}[/tex] V² – U² = 2as V² –0² = 2 (10)(5) V² = 100 V = 10 m/s [tex]\\[/tex] Hence, kinetic Energy = [tex] = \frac{1}{2} \times 1 \times {(10)}^{2} \\ \\ = \frac{1}{2} \times 100 \\ \\ = 50 \: joules[/tex] Hence, the kinetic energy = 50 J and potential energy = 50 J [tex] \\ [/tex] [tex]\huge \purple{ \underline{ \underline{ \mathtt{ \: ⭐hope \: \: this \: \: helps \: \: you⭐}}}}[/tex] Reply
[tex] \huge{ \mathtt{Given :-}}[/tex]
[tex] \huge{ \mathtt{To \: Find :-}}[/tex]
[tex] \huge{ \mathtt{Solution:-}}[/tex]
Potential energy = mgh
= 1 × 10 × 5 = 50 Joules.
Kinetic energy = 1/2×m×v²
= 1/2 × 1 × V² => V = ?
[tex]\\ [/tex]
[tex]\huge\red{Using \: Third \: equation \: of \: motion}[/tex]
V² – U² = 2as
V² –0² = 2 (10)(5)
V² = 100
V = 10 m/s
[tex]\\[/tex]
Hence, kinetic Energy =
[tex] = \frac{1}{2} \times 1 \times {(10)}^{2} \\ \\ = \frac{1}{2} \times 100 \\ \\ = 50 \: joules[/tex]
Hence, the kinetic energy = 50 J and potential energy = 50 J
[tex] \\ [/tex]
[tex]\huge \purple{ \underline{ \underline{ \mathtt{ \: ⭐hope \: \: this \: \: helps \: \: you⭐}}}}[/tex]