Answer :– The compound interest is Rs 81.6. To find :– The compound interest on Rs 1000 for two years at 4% per annum. Solution :– Before finding the compound interest, let’s find the amount! We know that :– [tex] \underline{ \boxed{\sf Amount = Principal \left(1 + \dfrac{Rate}{100} \right)^{Time}}}[/tex] Here, Principal = Rs 1000. Rate = 4% per annum. Time = 2 years. Therefore :– [tex] \longrightarrow\rm Amount = 1000 \left( 1 + \dfrac{4}{100} \right)^{2} [/tex] [tex] \longrightarrow\rm Amount = 1000 \left(1 + \dfrac{1}{25} \right)^{2} [/tex] [tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{1 \times 25 + 1 \times 1}{25} \right)[/tex] [tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{25 + 1}{25} \right)^{2} [/tex] [tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{26}{25} \right)^{2} [/tex] [tex] \longrightarrow\rm Amount = 1000 \times \dfrac{26}{25} \times \dfrac{26}{25} [/tex] [tex] \longrightarrow\rm Amount = 1000 \times \dfrac{676}{625} [/tex] [tex] \longrightarrow\rm Amount = \dfrac{676000}{625} [/tex] [tex] \longrightarrow\overline{ \boxed{ \rm Amount = Rs \: 1081.6}}[/tex] ––––––––––––––––––––––––––––––––––––––– Now, let’s find the compound interest! We know that :– [tex] \underline{ \boxed{ \sf CI = Amount – Principal}}[/tex] Where, CI = Compound Interest. Here, Amount = Rs 1081.6. Principal = Rs 1000. Therefore, [tex] \longmapsto\bf CI = 1081.6 – 1000[/tex] [tex] \longmapsto\bf CI = Rs \: 81.6[/tex] ________________________________ Hence :– The compound interest is Rs 81.6. Reply
Answer :–
To find :–
Solution :–
We know that :–
[tex] \underline{ \boxed{\sf Amount = Principal \left(1 + \dfrac{Rate}{100} \right)^{Time}}}[/tex]
Here,
Therefore :–
[tex] \longrightarrow\rm Amount = 1000 \left( 1 + \dfrac{4}{100} \right)^{2} [/tex]
[tex] \longrightarrow\rm Amount = 1000 \left(1 + \dfrac{1}{25} \right)^{2} [/tex]
[tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{1 \times 25 + 1 \times 1}{25} \right)[/tex]
[tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{25 + 1}{25} \right)^{2} [/tex]
[tex] \longrightarrow\rm Amount = 1000 \left( \dfrac{26}{25} \right)^{2} [/tex]
[tex] \longrightarrow\rm Amount = 1000 \times \dfrac{26}{25} \times \dfrac{26}{25} [/tex]
[tex] \longrightarrow\rm Amount = 1000 \times \dfrac{676}{625} [/tex]
[tex] \longrightarrow\rm Amount = \dfrac{676000}{625} [/tex]
[tex] \longrightarrow\overline{ \boxed{ \rm Amount = Rs \: 1081.6}}[/tex]
–––––––––––––––––––––––––––––––––––––––
We know that :–
[tex] \underline{ \boxed{ \sf CI = Amount – Principal}}[/tex]
Where,
Here,
Therefore,
[tex] \longmapsto\bf CI = 1081.6 – 1000[/tex]
[tex] \longmapsto\bf CI = Rs \: 81.6[/tex]
________________________________
Hence :–