find a quadratic Plynomial each with the given numbers as the sum and product of its zeroes respectively -3/2√5, -1/2 About the author Rose
Answer: Let the zeroes of the polynomial are alpha and beta. alpha + beta = -3/2√5 alpha × beta = – 1/2 Then the polynomial is of the form, x² – (alpha + beta ) x + (alpha × beta) = 0 x² – (-3/2√5 ) x + (-1/2) = 0 x² + 3/2√5 × x – 1/2 = 0 x² + 3x/2√5 – 1/2 = 0 2√5x²/2√5 + 3x/2√5 – √5/2√5 = 0 2√5x² + 3x – √5 = 0 Then the polynomial be 2√5x² + 3x – √5 I hope this will help u. Please add this to the brainlist. Reply
Answer:
Let the zeroes of the polynomial are alpha and beta.
alpha + beta = -3/2√5
alpha × beta = – 1/2
Then the polynomial is of the form,
x² – (alpha + beta ) x + (alpha × beta) = 0
x² – (-3/2√5 ) x + (-1/2) = 0
x² + 3/2√5 × x – 1/2 = 0
x² + 3x/2√5 – 1/2 = 0
2√5x²/2√5 + 3x/2√5 – √5/2√5 = 0
2√5x² + 3x – √5 = 0
Then the polynomial be 2√5x² + 3x – √5
I hope this will help u. Please add this to the brainlist.