a well with 14 inside diameter is dug 8m deep. the earth taken out of it has been evenly spread all around it to a width of 21m to form an embarkment .find the height of the embarkment About the author Eliza
Given Diameter = 14m Radius = 7m Depth = 8m Let Height of embankment = Xm To find Height of the embankment ? Solution Volume of earth dug out from well = [tex]\sf{\red{πr²}} [/tex] ➲ [tex] \frac{22}{7} [/tex]× 7 × 7 × 8 [tex]\boxed{\text{→ 1232m³}}[/tex] The earth Spread out of width = 21m Area × h = 1232 [tex]\boxed{\text{➲π(R²-r²)h = 1232 }}[/tex] ➲[tex] \frac{22}{7} [/tex](28²-7²)h = 1232 ➲[tex] \frac{22}{7} [/tex](735)h= 1232 ➲h = [tex] \frac{1232×7}{22×735} [/tex] ➲h = [tex] \frac{8624}{16170} [/tex] [tex]\boxed{\text{ ➲h = 0.533m }}[/tex] [tex]\boxed{\text{➲h = 53.3cm }}[/tex] Height of embankment is 53.3cm Reply
Given
To find
Solution
Volume of earth dug out from well = [tex]\sf{\red{πr²}} [/tex]
➲ [tex] \frac{22}{7} [/tex]× 7 × 7 × 8
[tex]\boxed{\text{→ 1232m³}}[/tex]
The earth Spread out of width = 21m
Area × h = 1232
[tex]\boxed{\text{➲π(R²-r²)h = 1232 }}[/tex]
➲[tex] \frac{22}{7} [/tex](28²-7²)h = 1232
➲[tex] \frac{22}{7} [/tex](735)h= 1232
➲h = [tex] \frac{1232×7}{22×735} [/tex]
➲h = [tex] \frac{8624}{16170} [/tex]
[tex]\boxed{\text{ ➲h = 0.533m }}[/tex]
[tex]\boxed{\text{➲h = 53.3cm }}[/tex]
Height of embankment is 53.3cm