a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages About the author Serenity
Let the age of son = x. Then the age of man will be 3 times as old as his son = 3x. After 15 years: Age of son = x + 15. Age of man = 3x + 15. Given that Man will be only twice as old as his son. 3x + 15 = 2(x + 15) 3x + 15 = 2x + 30 3x = 2x + 15 x = 15. Therefore the age of son = 15 years. the age of man = 45 years. Hope this helps! Reply
Answer: Here is your answer: Let the present age of son be X years then the present age of father be 3X years After 15 years Son’s age = (X + 15) years and father’s = (3X + 15) According to the question, we have => (3X + 13) = 2(X + 15) => 3X + 15 = 2X + 30 => 3 X – 2 X = 30 – 15 => X = 15 .°. The present age of son = 15 years and present age of father = 3X = 15 × 3 = 45 years. Hope it helps you. mark me brainliest or follow me. thanks Reply
Let the age of son = x.
Then the age of man will be 3 times as old as his son = 3x.
After 15 years:
Age of son = x + 15.
Age of man = 3x + 15.
Given that Man will be only twice as old as his son.
3x + 15 = 2(x + 15)
3x + 15 = 2x + 30
3x = 2x + 15
x = 15.
Therefore the age of son = 15 years.
the age of man = 45 years.
Hope this helps!
Answer:
Here is your answer:
Let the present age of son be X years
then the present age of father be 3X years
After 15 years
Son’s age = (X + 15) years
and father’s = (3X + 15)
According to the question, we have
=> (3X + 13) = 2(X + 15)
=> 3X + 15 = 2X + 30
=> 3 X – 2 X = 30 – 15
=> X = 15
.°. The present age of son = 15 years
and present age of father = 3X = 15 × 3 = 45 years.
Hope it helps you. mark me brainliest or follow me.
thanks