a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages​

Question

a father is 3 times as older as his son . after 15 years , he will be twice as old as his son . find their present ages​

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Serenity 2 months 2021-07-27T14:14:11+00:00 2 Answers 0 views 0

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    0
    2021-07-27T14:15:23+00:00

    Let the age of son = x.

    Then the age of man will be 3 times as old as his son = 3x.

    After 15 years:

    Age of son = x + 15.

    Age of man = 3x + 15.

    Given that Man will be only twice as old as his son.

    3x + 15 = 2(x + 15)

    3x + 15 = 2x + 30

    3x = 2x + 15

    x = 15.

    Therefore the age of son = 15 years.

    the age of man = 45 years.

    Hope this helps!

    0
    2021-07-27T14:15:43+00:00

    Answer:

    Here is your answer:

    Let the present age of son be X years

    then the present age of father be 3X years

    After 15 years

    Son’s age = (X + 15) years

    and father’s = (3X + 15)

    According to the question, we have

    => (3X + 13) = 2(X + 15)

    => 3X + 15 = 2X + 30

    => 3 X 2 X = 30 15

    => X = 15

    .°. The present age of son = 15 years

    and present age of father = 3X = 15 × 3 = 45 years.

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    thanks

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