## A cylindrical jug of hight 24cm radius of base 7cm is full of milk to be served by the glasses in the shape of frustum of cone. Fi

Question

A cylindrical jug of hight 24cm radius of base 7cm is full of milk to be served by the glasses in the shape of frustum of cone. Find the number of glasses. That could be served if each glass is of hight 9cm and radii of its bases are 2cm and 1cm

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3 months 2021-07-17T13:54:59+00:00 1 Answers 0 views 0

1. ### Dimensions of cylindrical jug

Radius of base of cylindrical jug, r = 7 cm

Height of cylindrical jug, h = 24 cm

### So,

Quantity of milk contained in cylindrical jug is equals to   ### Dimensions of frustum shape glass

Height of glass, H = 9 cm

Radius of one end, x = 1 cm

Radius of other end, y = 2 cm

### So,

Quantity of milk contained in frustum shape glass is    Hence, number of glasses in which the whole quantity of milk in cylindrical jug be served in frustum shape glass is   Volume of cylinder = πr²h

T.S.A of cylinder = 2πrh + 2πr²

Volume of cone = ⅓ πr²h

C.S.A of cone = πrl

T.S.A of cone = πrl + πr²

Volume of cuboid = l × b × h

C.S.A of cuboid = 2(l + b)h

T.S.A of cuboid = 2(lb + bh + lh)

C.S.A of cube = 4a²

T.S.A of cube = 6a²

Volume of cube = a³

Volume of sphere = 4/3πr³

Surface area of sphere = 4πr²

Volume of hemisphere = ⅔ πr³

C.S.A of hemisphere = 2πr²

T.S.A of hemisphere = 3πr²