a cupper wire daimeter 0.5 mm and resistive of 1.6× 10 to the power of 8 ohm m what shoud be the wire of make resistence 10 ohm​

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1. Answer:

   Given

   Resistivity (ρ) = 1.6 × 10-8 Ω m

   Resistance (R) = 10 Ω

   Diameter (d) = 0.5 mm

   d = 5 × 10⁻⁴ m

   Hence, we will get radius

   Radius (r) = 0.25 mm

   r = 0.25 × 10⁻³ m

   r = 2.5 × 10⁻⁴ m

   We need to find the area of cross-section

   A = πr2

   A = (22/7)(2.5 × 10⁻⁴)2

   A = (22/7)(6.25×10⁻⁸)

   A = 1.964 × 10-7 m2

   Find out

   We have to find the length of the wire

   Let the length of the wire be L

   Formula

   We know that

   R = ρ (L) / (A)

   L = (R × A) / ρ

   Substituting the values in the above equation we get

   L = (10 × 1.964 × 10⁻⁷) / 1.6 × 10⁻⁸ m

   L = 1.964×10-6 /1.6 × 10-8

   L = 122.72 m

   If the diameter of the wire is doubled, the new diameter = 2 × 0.5 = 1mm = 0.001m

   Let new resistance be Rʹ

   R = ρ (L) / (A)

   R’ = ρ (L) / (4A)

   R’ = ρ (L) X 1/(4A)

   Hence, if diameter doubles, resistance becomes 1/4 times.

   Answer

   Therefore, the length of the wire is 122.7 m and the new resistance becomes 1/4 times.

   Explanation:

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