A chord 6 cm long is drawn in a circle with a diameter equal to 10 cm. Then the perpendicular distance from the centre is​

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A chord 6 cm long is drawn in a circle with a diameter equal to 10 cm. Then the perpendicular distance from the centre is​

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Caroline 5 months 2021-07-18T22:31:28+00:00 1 Answers 0 views 0

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    2021-07-18T22:32:59+00:00

    O is the centre of circle, radius of the circle=OA=r=10 cm, AB = ?, OC = 6 cm, C is point on chord AB & OC perpendicular to AB.

    \text{Now, In right triangle OAC,}

    \boxed{\bf{By\: Pythagoras\: Theorem}}

    \sf OA ² = AC² + CO²

    \sf Or, AC² = OA² - CO²

    \sf Or, AC² = 10² - 6² = 100 - 36 = 64

    \sf Or, AC² = 100 - 36

    \sf Or, AC² = 64

    \sf Or, AC² = 8²

    \sf Or, AC = 8

    \sf Or AB = AC + CB

    \sf Or AB = 8 + 8 ----------- (AC = CB)

    Or AB = 16 cm

    Therefore, length of chord = AB = 16 cm

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