A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​

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A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​

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Luna 2 years 2021-06-22T16:59:28+00:00 2 Answers 0 views 0

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  1. Amelia
    0
    2021-06-22T17:00:56+00:00
    Reply

    Appropriate Question:-

    A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m with velocity of 6m/s. Then its unifom acceleration??

    Given:–

    • A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s.

    To Find:–

    • It’s unifom acceleration

    Equation used:–

    • {\boxed{\bf{v^2=2as+u^2}}}

    Here,

    • v = Final Velocity
    • u = Initial Velocity
    • a = Acceleration
    • S = Displacement

    Solution:–

    Using, v² = 2as + u²

    Here,

    • v = 6m/s
    • S = 6m
    • u = 0m/s

    Putting Values,

    \sf \implies\:6^2=2\times a \times 6+0^2

    \sf \implies\:12a=36

    \sf \implies\:a=\dfrac{36}{12}

    \sf \implies\:a=\dfrac{9}{3}

    \bf \implies\:a=3ms^{-2}

    Hence, It’s Unifom Acceleration is 3m/s².

    ━━━━━━━━━━━━━━━━━━

    More Equations of Motion:-

    • \bf v=u+at
    • \bf S=ut+\dfrac{1}{2}at^2

    ━━━━━━━━━━━━━━━━━━

  2. Ayla
    0
    2021-06-22T17:01:14+00:00
    Reply

    Correct Question !!

    A body starts from rest and travels with a unifom acceleration a to make a displacement of 6m and its final velocity is 6m/s then its unifom acceleration is ?

    Given:–

    • Initial velocity ,u = 0m/s
    • Final velocity ,v = 6m/s
    • Displacement,s = 6m

    To Find:–

    • Acceleration ,a

    Solution:–

    ⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

    It is given that the body starts from rest & cover a displacement of 6 m with velocity 6m/s. We calculate the acceleration of the body . Using 3rd equation of motion

    • v² = u² + 2as

    where,

    • v denote final velocity
    • u denote initial velocity
    • a denote acceleration
    • s denote displacement

    Substitute the value we get

    :\implies 6² = 0² + 2×a × 6

    :\implies 36 = 0 + 12a

    :\implies 36 = 12a

    :\implies 12a = 36

    :\implies a = 36/12

    :\implies a = 3m/s²

    • Hence, the uniform acceleration of the body is 3m/s².

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