## A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​

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A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s then its unifom acceleration is​

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2 years 2021-06-22T16:59:28+00:00 2 Answers 0 views 0

1. ### Appropriate Question:-

A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m with velocity of 6m/s. Then its unifom acceleration??

### Given:–

• A body starts from rest and travels with a unifom acceleration a to make a displacement is 6m/s.

### To Find:–

• It’s unifom acceleration

### Equation used:–

• Here,

• v = Final Velocity
• u = Initial Velocity
• a = Acceleration
• S = Displacement

### Solution:–

Using, = 2as +

Here,

• v = 6m/s
• S = 6m
• u = 0m/s

Putting Values,     Hence, It’s Unifom Acceleration is 3m/.

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### More Equations of Motion:-

• • ━━━━━━━━━━━━━━━━━━

2. Correct Question !!

A body starts from rest and travels with a unifom acceleration a to make a displacement of 6m and its final velocity is 6m/s then its unifom acceleration is ?

Given:

• Initial velocity ,u = 0m/s
• Final velocity ,v = 6m/s
• Displacement,s = 6m

To Find:

• Acceleration ,a

Solution:

⠀⠀⠀⠀⠀⠀⠀⠀According to the Question

It is given that the body starts from rest & cover a displacement of 6 m with velocity 6m/s. We calculate the acceleration of the body . Using 3rd equation of motion

• = + 2as

where,

• v denote final velocity
• u denote initial velocity
• a denote acceleration
• s denote displacement

Substitute the value we get 6² = 0² + 2×a × 6 36 = 0 + 12a 36 = 12a 12a = 36 a = 36/12 a = 3m/

• Hence, the uniform acceleration of the body is 3m/.