a battery of 10 volt is connected to a capacitor of capacitance 0.1 if the battery is now removed and this capacitor is connected

Question

a battery of 10 volt is connected to a capacitor of capacitance 0.1 if the battery is now removed and this capacitor is connected to a parallel with another uncharged capacitor of capacitance 0.2 how much of electrostatic energy of the first capacitor is lost in the form of heat and electromagnetic radiation​

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Kennedy 2 years 2021-06-22T02:11:38+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-06-22T02:13:15+00:00

    Answer:

    geredyteye4w6e6r6gteygtigrty

    Explanation:

    5v

    0
    2021-06-22T02:13:34+00:00

    Answer:

    Capacitance of a charged capacitor, C

    1

    =4μF=4×10

    −6

    F

    Supply voltage, V

    1

    =200V

    Electrostatic energy stored in C1 is given by,

    E

    1

    =

    2

    1

    C

    1

    V

    1

    2

    =

    2

    1

    ×4×10

    −6

    ×(200)

    2

    =8×10

    −2

    J

    Capacitance of an uncharged capacitor, C

    2

    =2μF=2×10

    −6

    F

    When C

    2

    is connected to the circuit, the potential acquired by it is V

    2

    .

    According to the conservation of charge, initial charge on capacitor C

    1

    is equal to the final charge on capacitors, C

    1

    and C

    2

    ∴V

    2

    (C

    1

    +C

    2

    )=C

    1

    V

    1

    V

    2

    ×(4+2)×10

    −6

    =4×10

    −6

    ×200

    V

    2

    =

    3

    400

    V

    Electrostatic energy for the combination of two capacitors is given by,

    E

    2

    =

    2

    1

    (C

    1

    +C

    2

    )V

    2

    2

    =

    2

    1

    (2+4)×10

    −6

    ×(

    3

    400

    )

    2

    =5.33×10

    −2

    J

    Hence, amount of electrostatic energy lost by capacitor C

    1

    =E

    1

    −E

    2

    =0.08−0.0533=0.0267

    =2.67×10

    −2

    J

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