Answer: Given, common difference of the AP, d=5 We know that, a n =a 1 +(n−1)d Then, a 18 =a 1 +17×d a 13 =a 1 +12×d Solving the two equations, a 18 −a 13 =a 1 +17d−a 1 −12d a 18 −a 13 =5d, Substituting d=5, a 18 −a 13= 25 Reply
Answer:
Given, common difference of the AP,
d=5
We know that,
a
n
=a
1
+(n−1)d
Then,
a
18
=a
1
+17×d
a
13
=a
1
+12×d
Solving the two equations,
a
18
−a
13
=a
1
+17d−a
1
−12d
a
18
−a
13
=5d,
Substituting d=5,
a
18
−a
13= 25